P=12-0.03s^2

Solution for P=12-0.03s^2 equation:

=12-0.03P^2

We move all terms to the left:

-(12-0.03P^2)=0

We get rid of parentheses

0.03P^2-12=0

a = 0.03; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·0.03·(-12)
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.44}}{2*0.03}=\frac{0-\sqrt{1.44}}{0.06}
=-\frac{\sqrt{}}{0.06}
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.44}}{2*0.03}=\frac{0+\sqrt{1.44}}{0.06}
=\frac{\sqrt{}}{0.06}
$